Problem 1
linear-equations·★★★★★
The sum of the digits of a two-digit number is $9$. Also, $9$ times this number is twice the number obtained by reversing the order of the digits. Find the original number.
▶Answer
$18$
▶Step-by-step solution
- Let the tens digit be $x$ and the units digit be $y$. The original number is $10x + y$ and reversed number is $10y + x$.
- From the sum of digits: $x + y = 9$.
- From the second condition: $9(10x + y) = 2(10y + x) \implies 90x + 9y = 20y + 2x \implies 88x = 11y \implies y = 8x$.
- Substituting $y = 8x$ into $x + y = 9$ gives $9x = 9 \implies x = 1$ and $y = 8$.
- Therefore, the original number is $10(1) + 8 = 18$.