Problem 1
Basic Proportionality Theorem·★★★★★
In triangle ABC, D lies on AB and E lies on AC with $DE\parallel BC$. Prove that $AD/DB=AE/EC$.
▶Answer
$AD/DB=AE/EC$.
▶Step-by-step solution
- Triangles ADE and BDE have the same altitude to AB, so their area ratio is $AD/DB$.
- Triangles ADE and CDE have the same altitude to AC, so their area ratio is $AE/EC$.
- Triangles BDE and CDE lie between the same parallels DE and BC and have equal areas; equating the two ratios gives $AD/DB=AE/EC$.